64x^2+x=9999

Solution for 64x^2+x=9999 equation:

64x^2+x=9999

We move all terms to the left:

64x^2+x-(9999)=0

a = 64; b = 1; c = -9999;
Δ = b2-4ac
Δ = 12-4·64·(-9999)
Δ = 2559745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2559745}}{2*64}=\frac{-1-\sqrt{2559745}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2559745}}{2*64}=\frac{-1+\sqrt{2559745}}{128}
$